A particle P is projected Vertically upward from a point A . Six seconds later, another particle Q is projected vertically upward from A . Both P and Q reach A simultaneously. The ratio o f maximum heights reached by P and `Q=65 : 25`. Find the velocity of the projection of Q in `m//s`.

Explanation

To solve the problem step by step, we need to analyze the motion of both particles P and Q.

### Step 1: Understand the problem
Particle P is projected upwards from point A at time \( t = 0 \). Particle Q is projected 6 seconds later, at \( t = 6 \) seconds. Both particles reach point A simultaneously.

### Step 2: Define the time of flight for both particles
Let the time of flight for particle P be \( T \) seconds. Since particle Q is projected 6 seconds later, its time of flight will be \( T - 6 \) seconds.

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