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Velocity and acceleration of a particle ...

Velocity and acceleration of a particle at time `t=0`are `u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2` respectively. Find the velocity and displacement if particle at `t=2s.`

Text Solution

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Here , acceleration `veca=(4hati+2hatj)m//s^(2)`Is constant . So , we can apply `vecv=vecu+vecat"and"vecs=vecut+1/2vecat^(2)`
Sustituting tha proper values, we get
`vecv=(2hati+3hatj)+(2)(4hati+2hatj)=(10hati+7hatj)m//s`and
`vecs=(2)(2hati+3hatj)+1/2(2)^(2)(4hati+2hatj)=(12hati+10hatj)m`
Therefore , velocity and displacement of particle at `t=2s `are `(10hati+7hatj)m//s`and`(12hati+10hatj)m`respectively.
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