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Graph of velocity (v) versus time 't' fo...

Graph of velocity (v) versus time 't' for motion of a motorbike which starts from rest and moves along a stright road is given .
(a)Find the average acceleration for the time interval `t_(0)`=0 to `t_(1)`=6.0 s
(b) Estimate the time at which the acceleration has its greatest positive value and the value of the acceleration at that instant.
(c) When is the acceleration is zero ?
(d) Estimate the maximum negative value of the acceleration and the time at which it occurs.

Text Solution

Verified by Experts

The correct Answer is:
(a)`1.3 ms^(-2);`(b)`2ms^(-2) `at 3 s;(c) at ` t=6s "and for " tgt10 s;`(d)`-1.5 ms^(-2) `at 8s
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