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The acceleration of a particle is given ...

The acceleration of a particle is given by a (t)=(3.00 `m//s^(2)-(2.00 m/s^(3))`)t. (a) Find the initial speed `v_(0)` such that the particle will have the same x -coordinate at t =5.00 as it had at t=0. (b)What will be the velocity at t =5.00s?

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The correct Answer is:
(a)` 0.833 m//s` (b)`-9.17 m//s`
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