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An object O (real ) is placed at focus o...

An object O (real ) is placed at focus of an equi-biconvex lens as shown in. figure-I . The refractive index of lens is `mu = 1.5` and the radius of curvature of either suface of lens is R . The lens is surronded by air . In each statement of column-I some changes are made to situation given above and information regarding final image formed as a result is given in column-II . The distance between lens and object is unchanged in all statements of column-I. match the statements in column-I with resulting image in column-II.

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The correct Answer is:
A, B, C, D
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Knowledge Check

  • The power of a biconvex lens is 10 dioptre and the radius of curvature of each surface is 10 cm. Then the refractive index of the material of the lens is

    A
    `3/2`
    B
    `4/3`
    C
    `9/8`
    D
    `5/3`

  • The radius curvature of each surface of a convex lens of refractive index 1.5 is 40 cm. Calculate its power.

    A
    `2.5 D`
    B
    `2 D`
    C
    `1.5 D`
    D
    `1 D`

  • The focal length of a biconvex lens of refractive index 1.5 is 0.06m. Radii of curvature are in the ratio 1:2. Then radii of curvature of two lens surfaces are

    A
    `0.045 m, 0.09m`
    B
    `0.09m, 0.18m`
    C
    `0.04m, 0.08m`
    D
    `0.06m, 0.12m`

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    The refractive index of a material of a plano-concave lens is 5/3 , the radius of curvature is 0.3 m. The focal length of the lens in air is

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    A biconvex lens (mu=1.5) has radius of curvature 20cm (both). find its focal length.

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    The power in dioptre of an equi-convex lens with radii of curvature of 10cm and refractive index 1.6 is

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