Find `Lt_(xto1)(2x^(2)+3x+4)`.

Answer

To find the limit \( \lim_{x \to 1} (2x^2 + 3x + 4) \), we can follow these steps:

### Step 1: Identify the function
The function we are working with is:
\[ f(x) = 2x^2 + 3x + 4 \]

### Step 2: Substitute the limit value
We need to evaluate the limit as \( x \) approaches 1. We can directly substitute \( x = 1 \) into the function:
\[ f(1) = 2(1)^2 + 3(1) + 4 \]

### Step 3: Calculate each term
Now, we calculate each term in the expression:
- \( 2(1)^2 = 2 \)
- \( 3(1) = 3 \)
- The constant term is \( 4 \)

### Step 4: Add the results
Now we add these results together:
\[ f(1) = 2 + 3 + 4 \]

### Step 5: Final calculation
Calculating the sum:
\[ 2 + 3 = 5 \]
\[ 5 + 4 = 9 \]

### Conclusion
Thus, the limit is:
\[ \lim_{x \to 1} (2x^2 + 3x + 4) = 9 \]