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A cannon and a target are 5.10Km apart ...

A cannon and a target are 5.10Km apart and located at the same level. How soon will the shell launched with the initial velocity 240m/s reach the target in the absence of air drag?

Text Solution

Verified by Experts

Here, `v_(0)=240ms^(-1)`,R5.10km5100m,
`g=9.8ms^(-2), alpha=?" "R+(v_(0)^(2)sin2alpha)/(g)`
`sin2alpha=(Rg)/(V_(0)^(2))" "rArralpha=30^(@) or 60^(@)`
using = `T =(2v_(0)sinalpha)/(g)`
When, `alpha = 30^(@), T_(1)=(2xx240xx0.5)/(9.8)=24.5s`
When,`alpha=60^(@), T_(2)=(2xx240xx0.867)/(9.8)=42.42s`
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