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Two boys are standing at the ends A and ...

Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity `v_(1)` . The boy at A starts running simultaneously with velocity v and catches the other in a time t, where t is

A

`(a)/(sqrt(v^(2)+v_(1)^(2))`

B

`(a)/(v+v_(1))`

C

`(a)/(v-v_(1))`

D

`sqrt((a^(2))/(v^(2)-v_(1)^(2))`

Text Solution

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The correct Answer is:
D
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