A body of mass 2kg is projected from the ground with a velocity `20ms^(-1)` at an angle `30^(@)` with the vertical. If `t_(1)` is the time in seconds at which the body is projected and `t_(2)` is the time in seconds at which it reaches the ground, the change in momentum in `kgms^(-1)` during the time `(t_(2)-t_(1))` is

Options

A. 40
B. `40sqrt(3)`
C. `50sqrt(3)`
D. 60

Answer

B