`dy/dx(2x^2+1)^2`

The solution of 3x(1-x^2)y^2dy / dx+(2x^2-1)y^3=a x^3 is

dy/dx cos^2(x^2-1)

Solve: (dy)/(dx)=x/(x^2+1)

The solution of (dy)/(dx)=(x^2+y^2+1)/(2x y) satisfying y(1)=1 is given by

The solution of (dy)/(dx)=(x^2+y^2+1)/(2x y) satisfying y(1)=1 is given by

The solution of dy/dx = (x^2+y^2+1)/(2xy) satisfying y(1)=0 is given by A. a hyperbola B. a circle C. y^2 = (1+x ) -10 D. None

dy/dx + (1-2x)/x^2 y=1

The solution of the differential equation x=1+x y(dy)/(dx)+(x^2y^2)/(2!)((dy)/dx)^2+(x^3y^3)/(3!)((dy)/(dx))^3+... i s

If =(sqrt(a^2+x^2)+sqrt(a^2-x^2))/(sqrt(a^2+x^2)-sqrt(a^2-x^2)) , show that (dy)/(dx)=(2a^2)/(x^3){1+(a^2)/(sqrt(a^4-x^4))} .

Find the solution of (y dy/dx+2x)^2=(y^2+2x^2)[1+(dy/dx)^2] and hence find the curve passing through (1,0)