`dy/dx`+`(1-2x)/x^2`y=1

dy/dx+2x/(1+x^2)y=1/(x(1+x^2))

If (dy)/dx = (xy)/(x^2 + y^2), y(1) = 1 and y(x) = e then x =

dy/dx + frac{1-2x}{x^2} y = 1

Solve: dy/dx + frac{1-2x}{x^2} y =1

Solve: (dy)/(dx) + (2x)/(1+ x^(2)) y= (1)/((1+x^(2))^(2))

Solve: (dy)/(dx)=(1+y^2)/(1+x^2)

Solve the following differential equations. (dy)/(dx )=(1+y^2)/(1+x^2) if y=1 for x=0

The differential equations, find a particular solution satisfying the given condition: (x^3+x^2+x+1)(dy)/(dx)=2x^2+x ; y=1 when x = 0

dy/dx=(x-y+1)/(2x-2y+3)

(dy)/(dx)=(x+y+1)/(2x+2y+3)