Read the following information carefully and answer the questions given below:
There are six bikes - P, Q, R, S, T, U - parked in a row facing north direction, but not necessarily in the same order. The distances between two adjacent bikes are successive multiples of five (i.e. if the distance between the `1^(st)` and the `2^(nd)` bike is 5 m, `1^(st)` and the `3^(rd)` bike is 10 m and between `1^(st)` and `4^(th)` bike is 15 m and so on.)
Information regarding all the bikes is:
I. Bike R is to the immediate right of P and the distance between them is 25m.
II. Bike T is to the left of Bike U but not immediate left and the total distance between them is 75m.
III. The person who has Bike Q takes his bike as he wants to go to his office so he moves 32 m in south direction from there he turns to his right and moves 12 m then he turns `90^(@)` in clockwise direction and moves 16m and after walking 8 m in east direction, he finally reached to his office.
IV. The total distance between bike T and P is a multiple of 11.
V. There is only one bike is parked to the right of Bike Q.
VI. If Bike S starts moving in north direction and after walking 18 m it turns to the right and covers 45m before turning to right. After that it moves 2m in the same direction Now Bike S, Bike R and another Bike V (which is exactly between Bike S and Bike R) will be in a straight line manner.
If Bike S starts moving in north direction from its initial position and after walking 5 m it turns to the right and covers 45m and then turns to left and moves 5m. Now how far and in which direction is Bike S with respect to Bike T?

Options

A. `8sqrt3` m towards north-west
B. 30 m towards south-east
C. `10sqrt7`m towards north-east
D. `10sqrt10` m towards north-west

Answer

D

Explanation

From the given condition, Bike R is to the immediate right of P and the distance between them is 25m.

There is only one bike is parked to the right of Bike Q. The person who has Bike Q takes his bike as he wants to go to his office so he moves 32 m in south direction from there he turns to his right and moves 12 m then he turns `90^(@)` in clockwise direction and then moves 16m and after walking 8 m in east direction, he finally reached to his office.

Now, Bike R is to the immediate right of P and the distance between them is 25m. Bike T is to the left of Bike U but not immediate left and the total distance between them is 75m. So, Bike P cannot be at extreme left end and cannot be at third to extreme left end, as the distances between two adjacent bikes are successive multiples of five, so Bike T and Bike U cannot be placed according to the given condition.
So Bike P will second to the extreme left end and Bike R will be immediate right of Bike P. And according to the given conditions there will be two possible places for Bike T and Bike U-----


But it is given that the total distance between bike T and P is a multiple of 11. So from this case-1 will be eliminated. Now continue with case-2 there is only one place left for S. Also given that If Bike S starts moving in north direction and after walking 18 m it turns to the right and covers 45m before turning to right. After that it moves 2m in the same direction. Now Bike S, Bike R and another Bike V (which is exactly between Bike Sand Bike R) will be in a straight line manner.
So the final diagram will be-