Six persons A, B, C, D, E and F are sitting on six chairs which are arranged in two parallel rows in a rectangular formation equidistant from each other. They are either facing North or South Direction. The persons with even number of toys are sitting on the chairs which are to the North of the person with odd number of toys. They have different number of toys as shown in the figure below.

E is not facing B or F.A pair of two immediate neighbors are facing the same direction. Both the immediate neighbors of C are facing the same direction. The person sitting ahead of F has even number of toys. The Person who is facing B is an immediate neighbour of A. C is not facing the person having an even number of toys. Person sitting in front of A has less than 9 toys. There is a difference of two between the number of toys of B and C.
Who among the following has the most number of toys?

Options

A. E
B. D
C. B
D. F

Answer

D

Explanation

Step 1. From the information given in the question we have, There is a difference of two between the number of toys of B and C. It means B and Care either sitting on chairs with 8 and 6 toys or on the chairs with 3 and 5 toys. Both the immediate neighbors of C are facing the same direction. It means Chas two immediate neighbors so C must be sitting on the chair with three toys while B must be sitting on the chair with 5 toys. The person sitting ahead of F has even number of toys. It means F has 9 toys. C is not facing the person with even number of toys therefore C must be facing south. Person facing B is an immediate neighbour of A and F and B are facing to north as because both the immediate neighbours of C face to same direction and B faces to north. It means A has two toys. Person sitting in front of A has less than 9 toys, Word front suggest A is facing towards South. E is not facing B or F. It means E is facing towards North. A pair.of two immediate neighbors are facing the same direction. It means A and D are facing towards south.
So we have our final solution as