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What approximate value will come in plac...

What approximate value will come in place of question mark (?) in the following questions. (You are not expected to calculate the exact value)
`(33.33 xx 80.989 div 99.99) + 3.024 - ? = 4.012`

A

20

B

26

C

34

D

16

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( (33.33 \times 80.989 \div 99.99) + 3.024 - ? = 4.012 \) and find the approximate value of the question mark (?), we can follow these steps: ### Step 1: Rewrite the equation We start with the equation: \[ (33.33 \times 80.989 \div 99.99) + 3.024 - ? = 4.012 \] We can denote the unknown value as \( x \): \[ (33.33 \times 80.989 \div 99.99) + 3.024 - x = 4.012 \] ### Step 2: Isolate \( x \) To isolate \( x \), we can rearrange the equation: \[ (33.33 \times 80.989 \div 99.99) + 3.024 = 4.012 + x \] Thus, \[ x = (33.33 \times 80.989 \div 99.99) + 3.024 - 4.012 \] ### Step 3: Approximate the values Next, we will approximate the values: - \( 33.33 \) is approximately \( 33 \). - \( 80.989 \) is approximately \( 81 \). - \( 99.99 \) is approximately \( 100 \). - \( 3.024 \) is approximately \( 3 \). - \( 4.012 \) is approximately \( 4 \). ### Step 4: Substitute the approximated values Substituting the approximated values into the equation gives us: \[ x = \left(33 \times 81 \div 100\right) + 3 - 4 \] ### Step 5: Perform the multiplication and division Calculate \( 33 \times 81 \): \[ 33 \times 81 = 2673 \] Now divide by \( 100 \): \[ 2673 \div 100 = 26.73 \] ### Step 6: Substitute back into the equation Now substitute back into the equation for \( x \): \[ x = 26.73 + 3 - 4 \] This simplifies to: \[ x = 26.73 + 3 - 4 = 26.73 + (-1) = 25.73 \] ### Step 7: Round to the nearest integer Since we are looking for an approximate value, we round \( 25.73 \) to the nearest integer: \[ x \approx 26 \] ### Final Answer Thus, the approximate value that will come in place of the question mark (?) is: \[ \boxed{26} \]
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ADDA247-NUMBER SYSTEM, SIMPLIFICATION AND APPROXIMATION -PRELIMS QUESTIONS (LEVEL - 2)
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