A boy after giving away 80 % of his pocket money to one companion and 6 % of the reminder to another , has Rs 94 left with him . How much pocket money did the boy have in the beginning ?

Answer

To find out how much pocket money the boy had in the beginning, we can follow these steps:

### Step 1: Define the initial amount of pocket money
Let the initial amount of pocket money be \( x \).

### Step 2: Calculate the amount given away to the first companion
The boy gives away 80% of his pocket money to one companion. Therefore, the amount given away is:
\[ \text{Amount given to first companion} = 0.80x \]

### Step 3: Calculate the remaining amount after the first companion
After giving away 80%, the remaining amount of pocket money is:
\[ \text{Remaining amount} = x - 0.80x = 0.20x \]

### Step 4: Calculate the amount given away to the second companion
The boy then gives away 6% of the remaining amount to another companion. The amount given to the second companion is:
\[ \text{Amount given to second companion} = 0.06 \times (0.20x) = 0.012x \]

### Step 5: Calculate the amount left with the boy
After giving away the amount to the second companion, the amount left with the boy is:
\[ \text{Amount left} = \text{Remaining amount} - \text{Amount given to second companion} \]
\[ \text{Amount left} = 0.20x - 0.012x = 0.188x \]

### Step 6: Set up the equation based on the amount left
According to the problem, the boy has Rs 94 left with him. Therefore, we can set up the equation:
\[ 0.188x = 94 \]

### Step 7: Solve for \( x \)
To find \( x \), we divide both sides of the equation by 0.188:
\[ x = \frac{94}{0.188} \]
Calculating this gives:
\[ x \approx 500 \]

### Conclusion
The boy had Rs 500 in the beginning.

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