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Himanshu invested Rs 42000 in business ....

Himanshu invested Rs 42000 in business . After 4 months , Kapil joins him with an investement of Rs P . If at the end of the year the profit is Rs 62000 and profit share of Himanshu is Rs 42000 . Find the value of P .

A

A)Rs 25000

B

B)Rs 30000

C

C)Rs 28000

D

D)Rs 38000

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the investments made by Himanshu and Kapil, the time they invested, and the profit distribution. ### Step-by-Step Solution: 1. **Identify the Investments and Time:** - Himanshu's investment = Rs 42,000 - Kapil's investment = Rs P (unknown) - Time invested by Himanshu = 12 months (1 year) - Time invested by Kapil = 8 months (since he joins after 4 months) 2. **Calculate the Investment Time Product:** - For Himanshu: \[ \text{Investment Time Product} = 42000 \times 12 = 504000 \] - For Kapil: \[ \text{Investment Time Product} = P \times 8 \] 3. **Set Up the Profit Sharing Ratio:** - The total profit at the end of the year = Rs 62,000 - Himanshu's share of the profit = Rs 42,000 - Kapil's share of the profit = Total profit - Himanshu's profit = \(62000 - 42000 = 20000\) 4. **Establish the Ratio of Profits:** - The profit ratio is based on the investment time products: \[ \frac{Himanshu's \, Profit}{Kapil's \, Profit} = \frac{504000}{8P} \] - We know that: \[ \frac{42000}{20000} = \frac{21}{10} \] 5. **Set Up the Equation:** \[ \frac{504000}{8P} = \frac{21}{10} \] 6. **Cross Multiply to Solve for P:** \[ 504000 \times 10 = 21 \times 8P \] \[ 5040000 = 168P \] 7. **Solve for P:** \[ P = \frac{5040000}{168} = 30000 \] Thus, the value of P is Rs 30,000. ### Final Answer: The value of P is Rs 30,000.
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