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The population of a city in 2017 increas...

The population of a city in 2017 increased by `12.5%` from 2016 and in 2018 it decreased by 8% with respect to previous year and in 2019 it again increased by 15% with respect to previous year. If in 2019, the population of the city is 1190250, then what was the population of city in 2016?

A

900000

B

1000000

C

850000

D

950000

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AI Generated Solution

The correct Answer is:
To find the population of the city in 2016, we will work backward from the population in 2019, applying the percentage changes for each year step by step. ### Step 1: Understand the population in 2019 We know that the population in 2019 is 1,190,250. ### Step 2: Calculate the population for 2018 In 2019, the population increased by 15% compared to 2018. Let the population in 2018 be \( P_{2018} \). Using the formula for percentage increase: \[ P_{2019} = P_{2018} \times \left(1 + \frac{15}{100}\right) \] This can be rearranged to find \( P_{2018} \): \[ P_{2018} = \frac{P_{2019}}{1 + \frac{15}{100}} = \frac{1,190,250}{1.15} \] Calculating \( P_{2018} \): \[ P_{2018} = \frac{1,190,250}{1.15} = 1,034,500 \] ### Step 3: Calculate the population for 2017 In 2018, the population decreased by 8% compared to 2017. Let the population in 2017 be \( P_{2017} \). Using the formula for percentage decrease: \[ P_{2018} = P_{2017} \times \left(1 - \frac{8}{100}\right) \] This can be rearranged to find \( P_{2017} \): \[ P_{2017} = \frac{P_{2018}}{1 - \frac{8}{100}} = \frac{1,034,500}{0.92} \] Calculating \( P_{2017} \): \[ P_{2017} = \frac{1,034,500}{0.92} = 1,123,913.04 \approx 1,123,913 \] ### Step 4: Calculate the population for 2016 In 2017, the population increased by 12.5% compared to 2016. Let the population in 2016 be \( P_{2016} \). Using the formula for percentage increase: \[ P_{2017} = P_{2016} \times \left(1 + \frac{12.5}{100}\right) \] This can be rearranged to find \( P_{2016} \): \[ P_{2016} = \frac{P_{2017}}{1 + \frac{12.5}{100}} = \frac{1,123,913}{1.125} \] Calculating \( P_{2016} \): \[ P_{2016} = \frac{1,123,913}{1.125} = 999,999.78 \approx 1,000,000 \] ### Conclusion The population of the city in 2016 was approximately **1,000,000**. ---
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