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The SI on a certain sum of money for 2 y...

The SI on a certain sum of money for 2 years at 10% per annum is Rs. 400, find Cl at the same rate and for the same time.

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To solve the problem step by step, we will first find the principal amount using the given simple interest, and then we will calculate the compound interest. ### Step 1: Understand the formula for Simple Interest (SI) The formula for Simple Interest is: \[ SI = \frac{P \times R \times T}{100} \] Where: - \( SI \) = Simple Interest - \( P \) = Principal amount - \( R \) = Rate of interest (per annum) - \( T \) = Time (in years) ### Step 2: Substitute the known values into the SI formula Given: - \( SI = 400 \) (for 2 years) - \( R = 10\% \) - \( T = 2 \) years Substituting these values into the formula: \[ 400 = \frac{P \times 10 \times 2}{100} \] ### Step 3: Simplify the equation First, simplify the right side: \[ 400 = \frac{20P}{100} \] This simplifies to: \[ 400 = \frac{P}{5} \] ### Step 4: Solve for Principal (P) To find \( P \), multiply both sides by 5: \[ P = 400 \times 5 = 2000 \] So, the principal amount \( P \) is Rs. 2000. ### Step 5: Calculate the Compound Interest (CI) The formula for Compound Interest is: \[ A = P \left(1 + \frac{R}{100}\right)^T \] Where \( A \) is the total amount after time \( T \). Substituting the known values: \[ A = 2000 \left(1 + \frac{10}{100}\right)^2 \] This simplifies to: \[ A = 2000 \left(1 + 0.1\right)^2 = 2000 \left(1.1\right)^2 \] ### Step 6: Calculate \( (1.1)^2 \) Calculating \( (1.1)^2 \): \[ (1.1)^2 = 1.21 \] So, \[ A = 2000 \times 1.21 = 2420 \] ### Step 7: Find Compound Interest (CI) Now, to find the Compound Interest: \[ CI = A - P = 2420 - 2000 = 420 \] ### Final Answer The Compound Interest (CI) at the same rate and for the same time is Rs. 420. ---
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