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A sum of money becomes 8 times in 1.5 ye...

A sum of money becomes 8 times in 1.5 year if compounded half yearly. How much time it will take to become 81 times if compounded yearly.

A

A)4 years

B

B)9 years

C

C)3 years

D

D)5years

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will break it down into manageable parts. ### Step 1: Understand the first case (Compounded Half-Yearly) We know that a sum of money becomes 8 times in 1.5 years when compounded half-yearly. ### Step 2: Determine the number of compounding cycles Since the interest is compounded half-yearly, we need to double the time given to find the number of compounding cycles: - Time = 1.5 years - Number of cycles = 2 * Time = 2 * 1.5 = 3 cycles ### Step 3: Set up the equation for the amount The formula for compound interest is: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) = final amount - \( P \) = principal amount - \( r \) = annual interest rate - \( n \) = number of times interest is compounded per year - \( t \) = time in years In our case, since the amount becomes 8 times the principal: \[ A = 8P \] ### Step 4: Find the ratio for one cycle The ratio of the amount to the principal after 3 cycles is: \[ \frac{A}{P} = 8 \] Thus: \[ \left(1 + \frac{r}{2}\right)^3 = 8 \] Taking the cube root of both sides: \[ 1 + \frac{r}{2} = 2 \] So: \[ \frac{r}{2} = 1 \] This gives: \[ r = 2 \text{ (or 200% per annum)} \] ### Step 5: Understand the second case (Compounded Yearly) Now we need to find out how long it will take for the amount to become 81 times when compounded yearly. ### Step 6: Set up the equation for the second case Using the same compound interest formula, we want: \[ A = 81P \] So: \[ \frac{A}{P} = 81 \] This can be expressed as: \[ (1 + r)^t = 81 \] ### Step 7: Substitute the interest rate From the first case, we found that the annual interest rate \( r = 2 \) (or 200%). Therefore: \[ (1 + 2)^t = 81 \] This simplifies to: \[ 3^t = 81 \] ### Step 8: Solve for \( t \) Since \( 81 = 3^4 \), we can set the exponents equal to each other: \[ t = 4 \] ### Conclusion Thus, it will take **4 years** for the sum of money to become 81 times when compounded yearly. ---
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