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4 yrs ago A was four yrs younger than B....

4 yrs ago A was four yrs younger than B. 6 yrs hence ratio of ages of A to B will be 16:17. Find the sum of ages of both 4 yrs ago.

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To solve the problem step by step, we will define the ages of A and B and use the information given in the question to find their ages. ### Step 1: Define the ages of A and B four years ago Let the age of A four years ago be \( x \). Since A was four years younger than B at that time, we can express B's age four years ago as: \[ \text{Age of B four years ago} = x + 4 \] ### Step 2: Express their current ages Since four years have passed since then, we can express their current ages as: \[ \text{Current age of A} = x + 4 \] \[ \text{Current age of B} = (x + 4) + 4 = x + 8 \] ### Step 3: Express their ages six years hence Six years from now, their ages will be: \[ \text{Age of A six years hence} = (x + 4) + 6 = x + 10 \] \[ \text{Age of B six years hence} = (x + 8) + 6 = x + 14 \] ### Step 4: Set up the ratio of their ages six years hence According to the problem, the ratio of their ages six years hence will be \( 16:17 \). Therefore, we can write the equation: \[ \frac{x + 10}{x + 14} = \frac{16}{17} \] ### Step 5: Cross-multiply to solve for x Cross-multiplying gives us: \[ 17(x + 10) = 16(x + 14) \] Expanding both sides: \[ 17x + 170 = 16x + 224 \] ### Step 6: Rearrange the equation to isolate x Subtract \( 16x \) from both sides: \[ 17x - 16x + 170 = 224 \] This simplifies to: \[ x + 170 = 224 \] Now, subtract 170 from both sides: \[ x = 224 - 170 \] \[ x = 54 \] ### Step 7: Find the ages of A and B four years ago Now that we have \( x = 54 \), we can find the ages of A and B four years ago: \[ \text{Age of A four years ago} = x = 54 \] \[ \text{Age of B four years ago} = x + 4 = 54 + 4 = 58 \] ### Step 8: Calculate the sum of their ages four years ago Finally, we find the sum of their ages four years ago: \[ \text{Sum of ages} = 54 + 58 = 112 \] ### Final Answer The sum of the ages of A and B four years ago is \( \boxed{112} \). ---
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ADDA247-AVERAGE AND AGES-Previous Year Question
  1. 4 yrs ago A was four yrs younger than B. 6 yrs hence ratio of ages of ...

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  2. The ratio of ages of A and B 4 years ago was 5:3. The sum of present ...

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  3. Ratio of age of P 2 years ago to age of R 2 years hence is 1 : 2 and Q...

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  4. Average weight of a class is 60kg and average weight of boys in the cl...

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  5. Present age of Father and mother is in ratio of 12:11 and after 12 yea...

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  6. Ravi and Sneha got married 10 years ago and at that time ratio of thei...

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  7. If ratio of ages of P and Q before 4 year is 9 : 10 , after 12 years s...

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  8. Suresh was married 14 yrs ago and his present age is 3/2 times of the ...

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  9. A is 6 years younger than B and ratio of present age of B to C is 12:...

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  10. Amit's present age is 75% of Binny's present age where as present age...

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  11. My sister was born 26 yrs after my mother was born and I was born 28 ...

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  12. Six years ago, the ratio of age of Kunal to Sagar was 6: 5 and four ye...

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  13. The ratio of the ages of Ram and Rahim 10yr ago was 1:3. The ratio of ...

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  14. Four years ago, ratio of age of A and B was 3: 4. Average of present ...

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  15. The ratio of the present age of A to B is 8: 5 and the average of the...

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  16. Ratio of ages of A and B, 4 years later is 8:9 respectively. If averag...

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  17. The average weight of a class of 45 girls is 53 kg. It was later foun...

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  18. If the difference between the present age of P and Q is three years a...

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  19. Average of 10 numbers is 35. if average of first 5 numbers is 40 and ...

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  20. Ratio of present age of A to B is 4: 3. If C is 4 years younger to B ...

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  21. 4 years hence the sum of ages of A and B will be 16 years more than th...

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