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Average of marks obtained by 120 candida...

Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of the failed candidates is 15, what is number of candidates who failed the examination?

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To solve the problem step by step, we will use the concept of averages and the method of allegations. ### Step 1: Understand the given data We know: - Total number of candidates = 120 - Average marks of all candidates = 35 - Average marks of passed candidates = 39 - Average marks of failed candidates = 15 ### Step 2: Calculate the total marks obtained by all candidates To find the total marks obtained by all candidates, we can use the formula: \[ \text{Total Marks} = \text{Average Marks} \times \text{Number of Candidates} \] Substituting the values: \[ \text{Total Marks} = 35 \times 120 = 4200 \] ### Step 3: Set up the equations for passed and failed candidates Let: - \( p \) = number of passed candidates - \( f \) = number of failed candidates From the problem, we know: \[ p + f = 120 \] ### Step 4: Express total marks in terms of passed and failed candidates The total marks can also be expressed as: \[ \text{Total Marks} = (\text{Average Marks of Passed} \times p) + (\text{Average Marks of Failed} \times f) \] Substituting the values: \[ 4200 = 39p + 15f \] ### Step 5: Solve the equations Now we have a system of equations: 1. \( p + f = 120 \) 2. \( 39p + 15f = 4200 \) From the first equation, we can express \( p \) in terms of \( f \): \[ p = 120 - f \] Substituting \( p \) in the second equation: \[ 39(120 - f) + 15f = 4200 \] Expanding this: \[ 4680 - 39f + 15f = 4200 \] Combining like terms: \[ 4680 - 24f = 4200 \] Now, isolate \( f \): \[ 4680 - 4200 = 24f \] \[ 480 = 24f \] \[ f = \frac{480}{24} = 20 \] ### Step 6: Conclusion The number of candidates who failed the examination is \( f = 20 \). ---
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