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A man can row 60 km in downstream and 35...

A man can row 60 km in downstream and 35 km in upstream in 9 hours. Also, he can row 49 km in upstream and 75 km in downstream in 12 hours. Find the rate of the current.

A

6 kmph

B

3 kmph

C

7.5 kmph

D

4 kmph

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first define the variables and then create equations based on the information given in the question. ### Step 1: Define Variables Let: - \( x \) = speed of the man in still water (in km/h) - \( y \) = speed of the current (in km/h) ### Step 2: Set Up the Equations From the problem, we have two scenarios: 1. **First Scenario**: - Distance downstream: 60 km - Distance upstream: 35 km - Total time: 9 hours The speed downstream is \( x + y \) and the speed upstream is \( x - y \). The equation for this scenario can be written as: \[ \frac{60}{x+y} + \frac{35}{x-y} = 9 \] 2. **Second Scenario**: - Distance downstream: 75 km - Distance upstream: 49 km - Total time: 12 hours The equation for this scenario can be written as: \[ \frac{75}{x+y} + \frac{49}{x-y} = 12 \] ### Step 3: Solve the Equations Now we have two equations: 1. \( \frac{60}{x+y} + \frac{35}{x-y} = 9 \) (Equation 1) 2. \( \frac{75}{x+y} + \frac{49}{x-y} = 12 \) (Equation 2) To solve these equations, we can multiply both sides of each equation by the denominators to eliminate the fractions. **From Equation 1**: Multiply through by \((x+y)(x-y)\): \[ 60(x-y) + 35(x+y) = 9(x+y)(x-y) \] **From Equation 2**: Multiply through by \((x+y)(x-y)\): \[ 75(x-y) + 49(x+y) = 12(x+y)(x-y) \] ### Step 4: Simplify the Equations Now we will simplify both equations. For Equation 1: \[ 60x - 60y + 35x + 35y = 9(x^2 - y^2) \] Combine like terms: \[ 95x - 25y = 9(x^2 - y^2) \] For Equation 2: \[ 75x - 75y + 49x + 49y = 12(x^2 - y^2) \] Combine like terms: \[ 124x - 26y = 12(x^2 - y^2) \] ### Step 5: Solve for \(x\) and \(y\) Now we have two equations in \(x\) and \(y\). We can solve these equations simultaneously. From the first equation: \[ 9x^2 - 95x + 25y + 9y^2 = 0 \] From the second equation: \[ 12x^2 - 124x + 26y + 12y^2 = 0 \] ### Step 6: Find the Value of \(y\) After solving these equations, we find that: - \( x = 11 \) km/h (speed of man in still water) - \( y = 4 \) km/h (speed of current) ### Final Answer The rate of the current is \( y = 4 \) km/h.
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ADDA247-BOAT AND STREAM -Prelims Questions (Level-1)
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  6. A boat which has a speed of 6 km/hr in still water cover 2 km in upstr...

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  7. Speed of boat in still water is 12 meter/sec and speed of current is 1...

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  8. Manoj starts swimming in upstream from point P after 12 sec he swims b...

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  9. A man can row 60 km in downstream and 35 km in upstream in 9 hours. Al...

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  10. Ratio between speed of boat in still water to speed of stream is 5: 1....

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  11. A boat can cover certain distance in upstream in 16 minutes and the sa...

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  12. A boat can cover 160 km downstream in half of the time in which it can...

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  13. Speed of boat in still water is 37.5% less than the speed of the boat ...

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  14. Difference between downstream and upstream speed of a boat is 6 km/h. ...

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  15. To cover a certain distance D in downstream, slower boat took 50% more...

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  16. Ratio of upstream speed to that of downstream speed is 3:5. If speed o...

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  17. Ratio of speed of a boat in upstream to in downstream is 11:14. If boa...

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  18. The time take by a boat in upstream is double than the time taken by i...

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  19. If ratio between speed of boat in still water and speed of stream is 2...

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  20. A boat takes a total of 10 hours to cover 84 km in upstream & 84 km in...

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