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In how many different ways can the lette...

In how many different ways can the letters of the word MATHEMATICS be arranged ?
MATHEMATICS शब्द के अक्षरों को कितने अलग-अलग तरीकों से व्यवस्थित किया जा सकता है?

A

`(10!)/(2)`

B

`(11!)/(2)`

C

`(11!)/(4)`

D

`(11!)/(8)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of different ways to arrange the letters of the word "MATHEMATICS", we can follow these steps: ### Step 1: Count the total number of letters The word "MATHEMATICS" consists of 11 letters. ### Step 2: Identify the repeated letters In the word "MATHEMATICS": - The letter 'M' appears 2 times. - The letter 'A' appears 2 times. - The letter 'T' appears 2 times. - The letters 'H', 'E', 'I', 'C', and 'S' each appear 1 time. ### Step 3: Use the formula for permutations of multiset The formula to calculate the number of arrangements of letters when there are repeated letters is given by: \[ \text{Number of arrangements} = \frac{n!}{p_1! \times p_2! \times p_3! \times \ldots} \] Where: - \( n \) is the total number of letters, - \( p_1, p_2, p_3, \ldots \) are the frequencies of the repeated letters. In our case: - \( n = 11 \) (total letters) - \( p_1 = 2 \) (for 'M') - \( p_2 = 2 \) (for 'A') - \( p_3 = 2 \) (for 'T') ### Step 4: Substitute the values into the formula Using the values we have: \[ \text{Number of arrangements} = \frac{11!}{2! \times 2! \times 2!} \] ### Step 5: Calculate the factorials Now we can calculate the factorials: - \( 11! = 39916800 \) - \( 2! = 2 \) Thus, we have: \[ \text{Number of arrangements} = \frac{39916800}{2 \times 2 \times 2} = \frac{39916800}{8} = 4989600 \] ### Final Answer The number of different ways to arrange the letters of the word "MATHEMATICS" is **4,989,600**. ---
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