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A five letter word is to be formed takin...

A five letter word is to be formed taking all letters - H , A , R , E and T .What is the probability that the word formed will contain all the vowels together ?

A

`(2)/(5)`

B

`(3)/(5)`

C

`(1)/(2)`

D

`(2)/(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability that a five-letter word formed from the letters H, A, R, E, and T contains all the vowels together, we can follow these steps: ### Step 1: Identify the letters and vowels We have the letters: H, A, R, E, T. Among these, the vowels are A and E. ### Step 2: Calculate the total number of arrangements of the letters To find the total number of arrangements of the five letters, we use the factorial of the number of letters: \[ \text{Total arrangements} = 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] ### Step 3: Treat the vowels as a single unit Since we want the vowels A and E to be together, we can treat them as a single entity or "block." Thus, we can represent the arrangement as: - Block (AE or EA) - H - R - T This gives us four units to arrange: (AE), H, R, T. ### Step 4: Calculate the arrangements of the blocks The number of arrangements of these four units is: \[ \text{Arrangements of blocks} = 4! = 4 \times 3 \times 2 \times 1 = 24 \] ### Step 5: Arrange the vowels within their block The vowels A and E can be arranged within their block in 2 ways (AE or EA): \[ \text{Arrangements of vowels} = 2! = 2 \] ### Step 6: Calculate the total arrangements with vowels together Now, we multiply the arrangements of the blocks by the arrangements of the vowels: \[ \text{Total arrangements with vowels together} = 4! \times 2! = 24 \times 2 = 48 \] ### Step 7: Calculate the probability The probability that the word formed will contain all the vowels together is given by the ratio of the number of favorable outcomes to the total outcomes: \[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{48}{120} \] ### Step 8: Simplify the probability Now, we simplify the fraction: \[ \frac{48}{120} = \frac{12}{30} = \frac{2}{5} \] Thus, the probability that the word formed will contain all the vowels together is: \[ \text{Probability} = \frac{2}{5} \] ### Final Answer The probability that the word formed will contain all the vowels together is \(\frac{2}{5}\). ---
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