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In a basket ,there are 5 green , 4 blue and 2 red balls in a basket What is the probability of both balls being blue or green ball , if 2 balls are picked from the basket ?

A

`(16)/(55)`

B

`(21)/(55)`

C

`(39)/(55)`

D

`(34)/(55)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability of picking two balls from a basket containing 5 green, 4 blue, and 2 red balls such that both balls are either blue or green, we can follow these steps: ### Step 1: Determine the total number of balls First, we need to find the total number of balls in the basket. - Green balls = 5 - Blue balls = 4 - Red balls = 2 Total balls = 5 + 4 + 2 = 11 ### Step 2: Calculate the total number of ways to pick 2 balls Next, we calculate the total number of ways to choose 2 balls from the 11 balls. Using the combination formula \( nCk = \frac{n!}{k!(n-k)!} \): \[ \text{Total ways to pick 2 balls} = 11C2 = \frac{11!}{2!(11-2)!} = \frac{11 \times 10}{2 \times 1} = 55 \] ### Step 3: Calculate the number of favorable outcomes for blue balls Now, we calculate the number of ways to pick 2 blue balls from the 4 blue balls. \[ \text{Ways to pick 2 blue balls} = 4C2 = \frac{4!}{2!(4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 \] ### Step 4: Calculate the number of favorable outcomes for green balls Next, we calculate the number of ways to pick 2 green balls from the 5 green balls. \[ \text{Ways to pick 2 green balls} = 5C2 = \frac{5!}{2!(5-2)!} = \frac{5 \times 4}{2 \times 1} = 10 \] ### Step 5: Calculate the total number of favorable outcomes Now, we add the number of ways to pick 2 blue balls and 2 green balls to find the total favorable outcomes. \[ \text{Total favorable outcomes} = \text{Ways to pick 2 blue balls} + \text{Ways to pick 2 green balls} = 6 + 10 = 16 \] ### Step 6: Calculate the probability Finally, we can calculate the probability of picking 2 balls that are either blue or green. \[ \text{Probability} = \frac{\text{Total favorable outcomes}}{\text{Total outcomes}} = \frac{16}{55} \] Thus, the probability of both balls being blue or green is \( \frac{16}{55} \). ---
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