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What will come in place of question mark...

What will come in place of question mark (?) in the following series questions?
39600,6600,?,330,110,55

A

A)1320

B

B)1650

C

C)1100

D

D)1160

Text Solution

AI Generated Solution

The correct Answer is:
To find the missing term in the series: 39600, 6600, ?, 330, 110, 55, we can analyze the pattern of the series step by step. ### Step 1: Identify the relationship between the terms We start with the first two terms: - First term: 39600 - Second term: 6600 To find the relationship, we can divide the first term by the second term: \[ \frac{39600}{6600} = 6 \] This indicates that the first term is 6 times the second term. ### Step 2: Analyze the next terms Next, we check the relationship between the second term (6600) and the fourth term (330): \[ \frac{6600}{330} = 20 \] This indicates that the second term is 20 times the fourth term. ### Step 3: Identify the pattern Now let's look at the relationship between the fourth term (330) and the fifth term (110): \[ \frac{330}{110} = 3 \] This indicates that the fourth term is 3 times the fifth term. ### Step 4: Continue with the next terms Now, let's check the relationship between the fifth term (110) and the sixth term (55): \[ \frac{110}{55} = 2 \] This indicates that the fifth term is 2 times the sixth term. ### Step 5: Establish the missing term Now we can see a pattern in the multipliers: - From 39600 to 6600, we divided by 6. - From 6600 to ?, we need to find the multiplier. - From ? to 330, we can find the multiplier as well. To find the missing term, we can use the established pattern. The multiplier from the second term (6600) to the third term (?) can be calculated as follows: - If we assume the multiplier is 5 (as we see a pattern of decreasing multipliers), we can calculate: \[ 6600 \div 5 = 1320 \] Thus, the missing term is 1320. ### Step 6: Verify the pattern Now we can verify the entire series: - 39600 ÷ 6 = 6600 - 6600 ÷ 5 = 1320 - 1320 ÷ 4 = 330 - 330 ÷ 3 = 110 - 110 ÷ 2 = 55 ### Conclusion The missing term in the series is **1320**.
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