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In each of the following questions, two ...

In each of the following questions, two equations (I) and (II) are given . Solve the equation and mark the correct option :
I. ` x^(2) + 30 x + 224 = 0 `
II. ` y^(2) + 35 y + 306 = 0 `

A

A)If ` x gt y `

B

B)If ` x ge y `

C

C)if ` x lt y `

D

D)If ` x le y`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given equations and determine the relationship between the values of \(x\) and \(y\), we will follow these steps: ### Step 1: Solve the first equation \(x^2 + 30x + 224 = 0\) 1. **Identify the equation**: \[ x^2 + 30x + 224 = 0 \] 2. **Factor the quadratic equation**: We need to find two numbers that multiply to \(224\) (the constant term) and add up to \(30\) (the coefficient of \(x\)). The numbers \(14\) and \(16\) satisfy this condition: \[ x^2 + 30x + 224 = (x + 14)(x + 16) = 0 \] 3. **Set each factor to zero**: \[ x + 14 = 0 \quad \text{or} \quad x + 16 = 0 \] 4. **Solve for \(x\)**: \[ x = -14 \quad \text{or} \quad x = -16 \] ### Step 2: Solve the second equation \(y^2 + 35y + 306 = 0\) 1. **Identify the equation**: \[ y^2 + 35y + 306 = 0 \] 2. **Factor the quadratic equation**: We need to find two numbers that multiply to \(306\) and add up to \(35\). The numbers \(17\) and \(18\) satisfy this condition: \[ y^2 + 35y + 306 = (y + 17)(y + 18) = 0 \] 3. **Set each factor to zero**: \[ y + 17 = 0 \quad \text{or} \quad y + 18 = 0 \] 4. **Solve for \(y\)**: \[ y = -17 \quad \text{or} \quad y = -18 \] ### Step 3: Compare the values of \(x\) and \(y\) Now we have the following values: - For \(x\): \(-14\) and \(-16\) - For \(y\): \(-17\) and \(-18\) ### Step 4: Determine the relationship between \(x\) and \(y\) 1. **Compare the values**: - For \(x = -14\): - Compare with \(y = -17\): \(-14 > -17\) - Compare with \(y = -18\): \(-14 > -18\) - For \(x = -16\): - Compare with \(y = -17\): \(-16 > -17\) - Compare with \(y = -18\): \(-16 > -18\) ### Conclusion In both cases, \(x\) is greater than \(y\). Therefore, the relationship we can conclude is: \[ x > y \] ### Final Answer The correct option is: - **Option A: \(x > y\)**
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