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Solve the given quadratic equations and ...

Solve the given quadratic equations and mark the correct option based on your answer
I. ` x^(2) + 7 x + 12 = 0`
II. ` y^(2) + 9 y + 20 = 0`

A

If ` x gt y`

B

If ` x ge y `

C

If ` x lt y `

D

If ` x le y`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given quadratic equations, we will follow these steps: ### Step 1: Solve the first quadratic equation \( x^2 + 7x + 12 = 0 \) 1. **Identify the coefficients**: Here, \( a = 1 \), \( b = 7 \), and \( c = 12 \). 2. **Factor the equation**: We need to find two numbers that multiply to \( c = 12 \) and add up to \( b = 7 \). The numbers are \( 3 \) and \( 4 \). 3. **Rewrite the equation**: \[ x^2 + 3x + 4x + 12 = 0 \] 4. **Group the terms**: \[ (x^2 + 3x) + (4x + 12) = 0 \] 5. **Factor by grouping**: \[ x(x + 3) + 4(x + 3) = 0 \] \[ (x + 3)(x + 4) = 0 \] 6. **Set each factor to zero**: \[ x + 3 = 0 \quad \Rightarrow \quad x = -3 \] \[ x + 4 = 0 \quad \Rightarrow \quad x = -4 \] ### Step 2: Solve the second quadratic equation \( y^2 + 9y + 20 = 0 \) 1. **Identify the coefficients**: Here, \( a = 1 \), \( b = 9 \), and \( c = 20 \). 2. **Factor the equation**: We need to find two numbers that multiply to \( c = 20 \) and add up to \( b = 9 \). The numbers are \( 4 \) and \( 5 \). 3. **Rewrite the equation**: \[ y^2 + 4y + 5y + 20 = 0 \] 4. **Group the terms**: \[ (y^2 + 4y) + (5y + 20) = 0 \] 5. **Factor by grouping**: \[ y(y + 4) + 5(y + 4) = 0 \] \[ (y + 4)(y + 5) = 0 \] 6. **Set each factor to zero**: \[ y + 4 = 0 \quad \Rightarrow \quad y = -4 \] \[ y + 5 = 0 \quad \Rightarrow \quad y = -5 \] ### Step 3: Compare the values of \( x \) and \( y \) - The solutions for \( x \) are \( -3 \) and \( -4 \). - The solutions for \( y \) are \( -4 \) and \( -5 \). Now we can compare: 1. For \( x = -4 \) and \( y = -4 \): \( x = y \) 2. For \( x = -3 \) and \( y = -4 \): \( x > y \) 3. For \( x = -4 \) and \( y = -5 \): \( x > y \) 4. For \( x = -3 \) and \( y = -5 \): \( x > y \) ### Conclusion From the comparisons, we can conclude that \( x \) is greater than or equal to \( y \). Therefore, the correct option is: **Option B: \( x \geq y \)** ---
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