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Solve the given quadratic equations and ...

Solve the given quadratic equations and mark the correct option based on your answer -
I. ` 4 x^(2) - 24 x + 32 = 0`
II. ` y^(2) - 8y + 15 = 0`

A

` x gt y`

B

` x lt y`

C

` x ge y `

D

x = y or there is no relationship

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AI Generated Solution

The correct Answer is:
To solve the given quadratic equations, we will follow these steps: ### Step 1: Solve the first equation \( 4x^2 - 24x + 32 = 0 \) 1. **Divide the entire equation by 4** to simplify it: \[ x^2 - 6x + 8 = 0 \] **Hint:** Dividing by a common factor simplifies the equation. 2. **Factor the quadratic equation**: We need two numbers that multiply to \(8\) (the constant term) and add up to \(-6\) (the coefficient of \(x\)). The numbers are \(-4\) and \(-2\): \[ (x - 4)(x - 2) = 0 \] **Hint:** Look for pairs of factors of the constant term that add up to the middle coefficient. 3. **Set each factor to zero**: \[ x - 4 = 0 \quad \Rightarrow \quad x = 4 \] \[ x - 2 = 0 \quad \Rightarrow \quad x = 2 \] **Hint:** Setting each factor equal to zero gives the possible solutions for \(x\). ### Step 2: Solve the second equation \( y^2 - 8y + 15 = 0 \) 1. **Factor the quadratic equation**: We need two numbers that multiply to \(15\) and add up to \(-8\). The numbers are \(-5\) and \(-3\): \[ (y - 5)(y - 3) = 0 \] **Hint:** Similar to the first equation, find pairs of factors for the constant term. 2. **Set each factor to zero**: \[ y - 5 = 0 \quad \Rightarrow \quad y = 5 \] \[ y - 3 = 0 \quad \Rightarrow \quad y = 3 \] **Hint:** Again, setting each factor equal to zero gives the possible solutions for \(y\). ### Step 3: Compare the values of \(x\) and \(y\) We found: - \(x = 4\) or \(x = 2\) - \(y = 5\) or \(y = 3\) Now we compare the values: - For \(x = 4\): - \(4 < 5\) (True) - \(4 > 3\) (True) - For \(x = 2\): - \(2 < 5\) (True) - \(2 < 3\) (True) ### Conclusion From the comparisons: - In the case of \(x = 4\), \(x\) is less than \(y\) when \(y = 5\) and greater when \(y = 3\). - In the case of \(x = 2\), \(x\) is less than both values of \(y\). Thus, we cannot establish a consistent relationship between \(x\) and \(y\) across all comparisons. Therefore, the conclusion is: **No relation exists between \(x\) and \(y\).**
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