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Quantity I : a train can cross a pole i...

Quantity I : a train can cross a pole in 24 sec with a speed of 75 km / h. Length of train
Quantity II : A train can cross a pole in 12 sec and a tunnel in 55.2 sec. If length of tunnel is 1800 m. length of train

A

Quantity I ` gt` Quantity II

B

Quantity I ` lt` Quantity II

C

Quantity I ` ge` Quantity II

D

Quantity I = Quantity II or no relation

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AI Generated Solution

The correct Answer is:
To solve the question, we need to find the lengths of the train in both Quantity I and Quantity II and then compare them. ### Quantity I: 1. **Given Data**: - Speed of the train = 75 km/h - Time taken to cross a pole = 24 seconds 2. **Convert Speed to m/s**: \[ \text{Speed in m/s} = \text{Speed in km/h} \times \frac{5}{18} \] \[ \text{Speed} = 75 \times \frac{5}{18} = \frac{375}{18} = 20.83 \text{ m/s} \] 3. **Calculate Length of the Train**: - The length of the train can be calculated using the formula: \[ \text{Length of train} = \text{Speed} \times \text{Time} \] \[ \text{Length} = 20.83 \text{ m/s} \times 24 \text{ s} = 500 \text{ m} \] ### Quantity II: 1. **Given Data**: - Time taken to cross a pole = 12 seconds - Time taken to cross a tunnel = 55.2 seconds - Length of the tunnel = 1800 m 2. **Let the speed of the train be \( x \) km/h and the length of the train be \( L \) m.** 3. **Set Up the Equations**: - From crossing the pole: \[ \frac{L}{x} = 12 \quad \text{(1)} \] - From crossing the tunnel: \[ \frac{L + 1800}{x} = 55.2 \quad \text{(2)} \] 4. **Express \( L \) from Equation (1)**: \[ L = 12x \quad \text{(3)} \] 5. **Substitute \( L \) in Equation (2)**: \[ \frac{12x + 1800}{x} = 55.2 \] \[ 12 + \frac{1800}{x} = 55.2 \] \[ \frac{1800}{x} = 55.2 - 12 \] \[ \frac{1800}{x} = 43.2 \] \[ x = \frac{1800}{43.2} = 41.67 \text{ km/h} \] 6. **Find Length of the Train Using \( x \)**: - Substitute \( x \) back into Equation (3): \[ L = 12 \times 41.67 = 500 \text{ m} \] ### Conclusion: - **Quantity I**: Length of the train = 500 m - **Quantity II**: Length of the train = 500 m Thus, both quantities are equal: \[ \text{Quantity I} = \text{Quantity II} = 500 \text{ m} \] ### Final Answer: Both quantities are equal. ---
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