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If the volumes of two cubes are in the r...

If the volumes of two cubes are in the ratio of 64 : 125, then what is the ratio of their total surface area ?

A

`9 : 16`

B

`4 : 5`

C

`16 : 25`

D

`64 : 125`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the total surface area of two cubes given that their volumes are in the ratio of 64:125. ### Step-by-Step Solution: 1. **Understand the Volume of a Cube**: The volume \( V \) of a cube with side length \( a \) is given by the formula: \[ V = a^3 \] For two cubes, let the side lengths be \( A \) and \( B \). Therefore, the volumes can be expressed as \( A^3 \) and \( B^3 \). 2. **Set Up the Volume Ratio**: We are given that the volumes of the two cubes are in the ratio: \[ \frac{A^3}{B^3} = \frac{64}{125} \] 3. **Take the Cube Root**: To find the ratio of the side lengths \( A \) and \( B \), we take the cube root of both sides: \[ \frac{A}{B} = \sqrt[3]{\frac{64}{125}} = \frac{\sqrt[3]{64}}{\sqrt[3]{125}} = \frac{4}{5} \] 4. **Calculate the Total Surface Area**: The total surface area \( S \) of a cube is given by the formula: \[ S = 6a^2 \] For our cubes, the total surface areas will be: \[ S_A = 6A^2 \quad \text{and} \quad S_B = 6B^2 \] 5. **Set Up the Surface Area Ratio**: We need to find the ratio of the total surface areas: \[ \frac{S_A}{S_B} = \frac{6A^2}{6B^2} = \frac{A^2}{B^2} \] 6. **Substitute the Ratio of Side Lengths**: We already have \( \frac{A}{B} = \frac{4}{5} \). Now we square this ratio: \[ \frac{A^2}{B^2} = \left(\frac{4}{5}\right)^2 = \frac{16}{25} \] 7. **Final Ratio of Total Surface Areas**: Therefore, the ratio of the total surface areas of the two cubes is: \[ \frac{S_A}{S_B} = \frac{16}{25} \] ### Conclusion: The ratio of the total surface area of the two cubes is \( 16:25 \).
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