`dy/dxcos(x+y)`=1

(6) (dy)/(dx)cos(x+y)=1

dy/dx cos(x-y) = 1

Find (dy)/(dx) ifcos(x-y)=1

The solution of the differential equation, x^(2)dy/dxcos""(1)/(x)-ysin""(1)/(x)=-1, where yto-1asxtooo is

Solve: (i) sin^(-1)((dy)/(dx))=x+y (ii) (dy)/(dx)=cos(x+y) (iii) (dy)/(dx)=(4x+y+1)^2

The solution of (x d x+y dy)/(x dy-y dx)=sqrt((1-x^2-y^2)/(x^2+y^2)) is

The solution of differential equation x^2=1 +(x/y)^(-1)(dy)/(dx)+((x/y)^-2((dy)/(dx))^2)/(2!)+((x/y)^(-3)((dy)/(dx))^3)/(3!)+... i s

If (sinx)^y=x+y , prove that (dy)/(dx)=(1-(x+y)ycotx)/((x+y)logsinx-1)

Solve the differential equation: (i) (1+y^2) + ( x - e^(tan^-1 y) ) dy/dx = 0 (ii) x dy/dx + cos^2 y = tan y dy/dx

(dy)/(dx)=(x+y+1)/(2x+2y+3)