A circle with centre (3, 2) passes through the point (6, 3).
What is the radius of the circle?

The equation of the circle having centre (1, 2) and passing through the point of intersection of the lines: 3x+y=14 and 2x+5y=18 is :

Find the equation of the circle which passes through the point (2,-2), and (3,4) and whose centre lies on the line x+y=2 .

The equation of circle having centre at (2,2) and passes through the point (4,5) is

Find the equation of the circle with centre at (1,-2) and passing through the centre of the circle x^2+y^2-4x+1=0

A circle passes through the points (-1,3) and (5,11) and its radius is 5. Then, its centre is

The equation of the circle which passes through the points of intersection of the circleS x^(2)+y^(2)-6 x=0 and x^(2)+y^(2)-6 y=0 and has centre at ((3)/(2), \(3)/(2)) is

If y=3 x is a tangent to a circle with centre (1,1) then the other tangent drawn through (0,0) to the circle is

A variablt circle passes through the fixed point (2,0) and touches the y -axis. Then the locus of its centre is