The coordinates of the vertices of a triangle are A(1, 1), B(5, 5), C(2, 5).
What is the length of CD?

If the coordinates of the vertices of a triangle ABC be A(-1,3,2), B(2,3,5), C(3,5,-2) then hat A =

Co-ordinates of the vertices of a triangle are (2, 0), (6, 0) and (1, 5). The distance between circumcentre and orthocentre is :

Find the area of the triangle vertices are (-5, -1), (3, -5), (5, 2)

The orthocentre of the triangle formed by A(1,2), B(-2,2), C(1,5) is

If the vertices of Delta ABC are A(5,-1) , B (-3,-2), C(-1,8) find the length of median through A.

IF the coordinates of the midpoints of the sides of a triangle are (1, 2), (0, -1), and (2,-1), find vertices of triangle.

If the midpoints of the sides of a triangle are (3, 4) (4, 6), and (5,7), find the coordinates of the vertices of the triangle.

What type of triangle is DeltaABC , with the coordinates of the vertices are A(-1, 0) B(1, 0) and C(0, sqrt(3)) . Calculate its Area. OR Find the values of k so that the area of the triangle with vertices (1, -1) (-4, 2k) and (-k, -5) is 24 sq. units.

A triangle with vertices (4, 0), (-1, -1), (3, 5) is :

Find the area of the triangle with vertices A(1,1,2), B(2,3,5) and C(1,5,5).