Draw the coordinate axes and mark the points A(1, 1), B(7, 1).

The eceentricity of the ellipse whose axes are the coordinate axes and which passes through the points (2,2) and (3,1) is

Prove by using the distance formula that the points A (1,2,3), B (-1, -1, -1) and C (3,5,7) are collinear.

If the area bounded by the curve y=f(x), the coordinate axes and the line x=x_1 is given by x_1 .e^(x_1) , then f(x) is equal to

The area of the triangle formed by the co-ordinate axes and a tangent to the curve xy=a^(2) at the point (x_(1), y_(1)) on it is :

If the equation of the locus of a point equidistant from the points (a_(1), b_(1)) and (a_(2), b_(2)) is : (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 , then c =

Draw number lines and locate the points on them (b) 1/8, 2/8, 3/8, 7/8

The triangle formed by the tangent to the curve f(x)=x^2+bx-b at the point (1,1) and the coordinate axes, lies in the first quadrant , if its area is 2, then the value of b is :

To divide a line segment AB in the ration 4:7 , a ray AX is first drawn such that BAX is an acute angle and then points A_1, A_2, A_3 , … located at equal distance on the ray AX and the point B is joined to

Write the coordinates of the points marked in the graph.

Write the coordinates of the points marked in the graph.