A circle with centre (3, 4) passes through the origin.
What is the radius of the circle?

The equation of the circle having centre (1, 2) and passing through the point of intersection of the lines: 3x+y=14 and 2x+5y=18 is :

Find the equation of the circle with centre at (1,-2) and passing through the centre of the circle x^2+y^2-4x+1=0

Find the equation of the circle which passes through the origin and belonges to the co-axial of circles whose limiting points are (1,2) and (4,3).

If y=3 x is a tangent to a circle with centre (1,1) then the other tangent drawn through (0,0) to the circle is

AP is the tangent to a circle with centre O as shown in the figure .IF angleP=45^(@) and radius of the circle is 5cm,then OP is equal to :

Let C be the circle with centre at (1, 1) and radius = 1. If T is the circle centred at (0, y), passing through origin and touching the circle C externally, then the radius of T is equal to :

The circle, which passes through the origin and whose centre lies on the line y = x and cutting the circle x^2+y^2-4x-6y+10 = 0 orthogonally is :

Equation of the circle with centre on the y-axis and pussing through the origin und the point (2, 3) is :