40 ml gaseous mixture of CO, `CH_(4)` and Ne was exploded with 10 ml of oxygen. On cooling, the gases occupied 36.5 ml. After treatment with KOH the volume reduced by 9 ml and again on treatment with alkaline pyrogallol, the volume further reduced, percentage of `CH_(4)` in the original mixture is

25 mL of a gaseous hydrocarbon is mixed with 150mL of oxygen in an eudiometer. After sparking and cooling back the mixture is passed through alkaline pyrogallol. The volume loss surffered in pyrogallol is 25mL. Calculate the molecular weight of hydrocarbon.

10 ml of a gaseous hydrocarbon is mixed with excess of oxygen and burnt . The gases are then cooled back . The reduction in volume was 25 ml . When the gases are passed into caustic potash , there is a further reduction in volume of 30 ml . If all volumes are measured under the laboratory conditions , the hydrocarbon is

The percentage by volume of C_(3)H_(8) in a gaseous mixture of C_(3)H_(8),CH_(4)andCO is 20. When 10 ml of the mixture is burnt in excess of O_(2) , the volume of CO_(2) produced is 2xml . Find the value of .x..

The weight of 1 litre of ozonised oxygen at STP was found to be 1.5gm. When 100 ml of this mixture at STP was treated with turpentine oil, the volume was reduced to 90 ml. The molecular weight of ozone is

10ml of mixture containing CO and N_(2) required 7 ml of oxygen to form CO_(2) and NO respectively on combution. Find the volume of N_(2) in the mixture.

When 20 ml of methane and 20 ml of oxygen are exploded together and the reaction mixture is cooled to laboratory temperature. The resulting volume of the mixture is