If 0.1 mole `H_(3)PO_(x)` is completely neutralised by 5.6g KOH then select the true statement.

12ml of H_(2)SO_(4) is completely neutralised with 15ml of 0.1N NaOH.What is the strength of acid in g L^(-1) ?

The mass of 80% pure H_(2)SO_(4) required to completely neutralise 60g of NaOH is

When IM H_2SO_3 is completely neutralised by sodium hydroxide, the heat liberated is 114.64 KJ. Enthalpy of neutralisation in KJ is?

Enthalpy of neutralization is defined as the enthalpy change when 1 mole of acid/base is completely neutralized by base/acid in dilute solution. For strong acid and strong base neutralization net chemical change is H_((aq))^(+) + OH_((aq))^(-) rarr H_(2)O_((l)), Delta H_(r )^(0) -= - 55.84 kJ//mol What is Delta H^(0) for complete neutralisation of strong diacidic base A(OH)_(2) " by " HNO_(3) ?

100ml 0.1M H_(3)PO_(4) is mixed with S0ml of 0.1M NaOH. What is the pH of the resultant solution? (Successive dissociation constant of H_(3) PO_(4) "are" 10^(-3) , 10^(-8) and 10^(-12) respectively ?

0.4 gm of polybasic acid H_(n)A (M.wt = 96) requires 0.5 gm NaOH for complete neutralisation. The number of replacable hydorgen atoms are (all the hydrogens are acidic)

Calculate the volume of 0.1 N H_(2)SO_(4) required to neutralise 200 ml. of 0.2 N NaOH solution. It is an acid base neutralisation reaction. Hence, at the neutralisation point. Number of equivalents of acid = Number of equivalents of base.

0.66 g of H_(3)PO_(2) will require x ml of 0.1M NaOH for complete neutralization. X is

The volume of 0.1 M NaOH will be required to neutralise 100 ml of 0.1 ml H_(3)PO_(4) using methyl red indicator to change the colour from pink (acidic medium) to yellow (basic medium) is 10^(x) . What is x?