Two elements X (at.mass 16) ard Y (at. mass 14) combine to form compounds A, which combine with a fixed mass of X in A, B and C is 1:3:5. If 32 parts by mas of X combines with 84 parts by mass of Y in B, then in C 16 parts by mass of X will combine with

Two elements X and Y have atomic weight of 14 and 16 . They form a series of compounds , A , B , C with fixed mass of X , Y is present in the ratio 1 :2 : 3 : 4 : 5 . If the compound A has 28 parts by weight of X and 16 parts by weight of Y , then the compound C will have 28 parts by weight of X and

A compound contains 50% of X (atomic mass 10) and 50% Y (at. mass 20). Which formula is certain to above data ?

One part of an clement A combines with two parts of B (another element). Six parts of clement C combine with four parts of element B. If A and C combine together the ratio of their masses will be governed by:

Hydrogen and oxygen combine in the ratio of 1:8 by mass of form water.

The atomic masses of two elements A and B are 20 and 40 respectively. If x gm of A contains Y atoms, how many atoms are present in 2x gm of B

x,y and z are the elements of a Dobereiner 's tried .If the atomic mass of 'x' is 7 and that of 'z' in 39. what should be the atomic mass of the 'y' ?

Suppose the elements X and Y combine to form two compounds XY_(2) and X_(2)Y_(2) . When 0.1 mole of XY_(2) weighs 10 g and 0.05 mole of X_(3)Y_(2) weighs 9 g, the atomic weights of X and Y are