Home
Class 12
CHEMISTRY
For A((s))+B((s))toC((s)),rate=k[A]^(1//...

For `A_((s))+B_((s))toC_((s))`,rate=`k[A]^(1//2)[B]^(2)`, if initial concentration of A and B are increased by factors 4 and 2 respectively, then the initial rate is changed by the factor:

A

4

B

6

C

8

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.3 To Q.32)|2 Videos

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|3 Videos

  • SURFACE CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Assertion - Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

The rate expression for the reaction A_((g))+B_((g))toC_((g)) is rate =kC_(A)^(2)C_(B)^(1//2) what changes in the initial concentrations of A and B will cause the rate of reaction to increase by a factor of eight?

The initial concentrations of A and B are same for A +2B harr 3C and when equilibrium concentrations of B and C are same then K_(c) is

In the system A_((s)) hArr 2B_((g)) + 3C_((g)) . If the concentration of C at equilibrium is increased by a factor of 2. It will casuse the equilibrium concentration of B to change to:

For the reaction A+B products, it is observed that (a) On doubling the initial concentration of A only, the rate of reaction is also doubled (b) On doubling the initial concentration of both A and B, there is a change by a factor of 8 in the rate of the reaction. The rate of this reaction is given by

The rare law for a reaction between th substances A and B is given by Rate =k[A]^(m)[B]^(n) On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

For the reaction A+Bto products, it is found that order of A is 1 and order of B is 1//2 . When concentrations of both A and B are increased four times the rate will increase by a factor

In a reaction, A+B to Product, rate is doubled when the concentration of B is doubled, and rate increases by a factor of 8 when the concentrations of both the reactants (A and B) are doubled, rate law for the reaction can be written as

If the surface area of a sphere of radius r is increasing uniformly at the rate cm^(2)//s , then the rate of change of its volume is :

If the electronic configurations of atoms A and B are 1S^2,2S^2, 2P^6,3S^2, 3P^1 and 2s2, 2p6 3S^2,3P^4 respectively, then What is the valency of atom A?