Home
Class 12
CHEMISTRY
Alpha decay of .(92)^(238)U forms .(90)^...

Alpha decay of `._(92)^(238)U` forms `._(90)^(234)Th`. What kind of decay from `._(90)^(234)Th` produces `._(84)^(234)Ac` ?

A

`alpha`

B

`beta`

C

`beta^(+)`(positron)

D

`gamma` -emission

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.3 To Q.32)|2 Videos

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|3 Videos

  • SURFACE CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Assertion - Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

The half-life of ._(92)^(238)U undergoing alpha - decay is 4.5xx10^(9) years. What is the activity of 1g sample of ._(92)^(238)U ?

We are given the following atomic masses : ._(92)^(238)U = 238.05079 u " " ._(2)^(4)He=4.00260 u ._(90)^(234)Th=234.04363u " " ._(1)^(1)H=1.00783 u ._(91)^(237)Pa=237.05121 u Here the symbol Pa is for the element protactinium (Z = 91) . Calculate the energy released during the alpha decay of ._(92)^(238)U .

We are given the following atomic masses : ._(92)^(238)U = 238.05079 u " " ._(2)^(4)He=4.00260 u ._(90)^(234)Th=234.04363u " " ._(1)^(1)H=1.00783 u ._(91)^(237)Pa=237.05121 u Here the symbol Pa is for the element protactinium (Z = 91) . Show that ._(92)^(238)U cannot spontaneously emit a proton.

The number of alpha particle in the nuclear reaction ""_(90)^(238) Th to ""_(81)^(212) Bi are : ____

The half life of ""_(92)^(238)U against alpha - decay is 13.86xx10^(16) s . The activity of 1 g sample of is

How many disintegrations per second will Occur in one gram of ._(92)^(238)U , if its half-life against alpha - decay is 1.42xx10^(-17)s ?

""_(92)^(238) U is the element of III B group , it undergoes decay as follows , ""_(92) ^(238) U overset(- alpha)(to) A overset(-alpha)(to) B overset(-beta)(to) C Which of the following statements is/are correct ?