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.(84)^(218)Po(t(1//2)=183 sec) decay to ...

`._(84)^(218)Po(t_(1//2)=183` sec) decay to `._(82)Pb(t_(1//2)=161` sec) by `alpha`-emission, while `Pb^(214)` is a `beta`-emitter. In an experiment starting with 1 mole of pure `Po^(218)`, how many time would be required for the number of nuclei of `._(82)^(214)Pb` to reach maximum ?

A

147.5

B

247.5

C

182

D

304

Text Solution

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The correct Answer is:
B
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