Home
Class 12
CHEMISTRY
Radioactive disintegration is a first o...

Radioactive disintegration is a first order reaction and it's rate depends only upon the nature of nucleus and does not depend upon external factors like temperature and pressure . The rate of radioactive disintegration (Activity) is represented as `- (dN)/(dt) = lambda N` , Where `lambda` = decay constant , N number of nuclei at time t , `N_(0)` = initial no. of nuclei.
The above equation after integration can be represented as `lambda = (2.303)/(t) "log" ((N_(0))/(N))`
What is the activity in Ci (curie) of 1.0 mole of Plutonium - 239 ? (`t_(1//2) = 24,000` years)

A

`1.49` Ci

B

`14.9` Ci

C

`5.513xx10^(11)` Ci

D

`None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.3 To Q.32)|2 Videos

  • CHEMICAL KINETIC & NUCLEAR CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|3 Videos

  • SURFACE CHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Assertion - Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

Radioactive disintegration is a first order reaction and it's rate depends only upon the nature of nucleus and does not depend upon external factors like temperature and pressure . The rate of radioactive disintegration (Activity) is represented as - (dN)/(dt) = lambda N , Where lambda = decay constant , N number of nuclei at time t , N_(0) = initial no. of nuclei. The above equation after integration can be represented as lambda = (2.303)/(t) "log" ((N_(0))/(N)) Calculate the half-life period of a radioactive element which remains only 1/16 of it's original amount in 4740 years :

Radioactive disintegration is a first order reaction and it's rate depends only upon the nature of nucleus and does not depend upon external factors like temperature and pressure . The rate of radioactive disintegration (Activity) is represented as - (dN)/(dt) = lambda N , Where lambda = decay constant , N number of nuclei at time t , N_(0) = initial no. of nuclei. The above equation after integration can be represented as lambda = (2.303)/(t) "log" ((N_(0))/(N)) Half-life period of U^(232) is 2.5 xx 10^(5) years . In how much time will the amount of U^(237) remaining be only 25% of the original amount ?

Doppler shift in frequency does not depend upon

(dc)/(dt) of a first order reaction depends on

The value of the universal gas constant R depends upon the

The value of the universal gas constant R depends upon the

The rate of reaction which does not involve gases, does not depend upon