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For the reaction Aunderset(k(2)"sec"^(-1...

For the reaction `Aunderset(k_(2)"sec"^(-1))overset(K_(1)"sec"^(-1))hArr B` following graph is given,
`k_(1) =4 xx 10^(-2)"sec"^(-1)`. Which is/are correct statement (s) (In 2=0.7 , In 8/7 =0.14)

A

equilibrium constant is 4.0

B

Time taken for the completion fo 50% fo equilibrium conc. Of B is 14 sec.

C

Time taken for the completion of 10% of initial conc. Of A is 2.8 sec.

D

Rate constant of backward reaction is `10^(-2)"sec"^(-1)`

Text Solution

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The correct Answer is:
A, B, C, D
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