Home
Class 11
CHEMISTRY
Ammonium chloride, crystalliazes in a bo...

Ammonium chloride, crystalliazes in a body centered cubic latteice iwh edge length of unit cell equal to 387pm. If the size of `Cl^(-)` ion is 181pm, the size of `NH_(4)^(+)` ion would be:

A

116pm

B

154pm

C

174pm

D

206pm

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.33 To Q.62)|1 Videos
  • SOLID STATE

    NARENDRA AWASTHI|Exercise Level 3 - One Or More Answers Are Correct|1 Videos
  • IONIC EEQUILIBRIUM

    NARENDRA AWASTHI|Exercise Assertin-Reason Type Questions|1 Videos
  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|20 Videos

Similar Questions

Explore conceptually related problems

AB crystallises in a bcc lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositely charged ions in the lattice is

NH_(4) X1 crystallises in bee lattice with edge length 383 pm. If the radius of NH_(4)^(+) ion is 154 pm ,calculate the radius of halide (X^(-) ) .

Lithium metal crystallizes in a body-centred cubic crystal. If the length of the side of the unit cell of lithium is 351pm, the atomic radius of the lithium will be

An element forms a body centered cubic (bcc) lattice with edge length of 300 pm. If the density of the element is 7.2 g cm^(-3) , the number of atoms present in 324 g of it approximately is

The radius of an atom of an element is 80 pm. If it crystallises as a body centred cubic lattice, what is th edge of its unit cell?

A given metal crystallises out with a cubic structure having edge length of 360 pm. If there are four metal atoms in one unit cell, what is the radius of one atom ?

CsBr crystallise in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02xx1023 mol^(-1) , the density of CsBr is

Sodium chloride crystallises into F.C.C lattice with Na occupying corner of a cube and the centre of each face, whereas Cl^(-) is occupies the centre of each edge and centre of the cube. The r_c //r_a value for NaCl is 0.53 and coordination number is 6,6. If all the ions present in one plane that is passing through the centre are removed, the formula of the resulting unit cell is

An element has a body centered cubic structure with a unit cell edge length of 400 pm. Atomic mass of an element is 24 gmol^(-1) What is the density of the element? (N_A = 6 times 10^23 mol^-1)

The following are some statements about the crystal lattice structure of sodium chloride i) If the corners of unit cell are occupied by Nation, the face edges are occupied by sodium ions ii) The ratio between radii of Na^+ and Cl^(-) ions is 0.93 iii) If the body centered ion of unit cell is Na^+ face centered ion in it is Cl^(-) The correct combination is