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The radius of Na^(+) is 95 pm and that o...

The radius of `Na^(+)` is 95 pm and that of `CI^(-)` ion is 181 pm. Hence the co-ordination number of `Na^(+)` will be

A

co-ordination no. Of `Na^(+)` is 6

B

co-ordination no. Of `Cl^(-)` is 8

C

length of the unit cell is 552 "pm"

D

length of the unit cell is 380"pm"

Text Solution

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The correct Answer is:
A, C
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