Home
Class 11
CHEMISTRY
Electronmagnetic radiations having lambd...

Electronmagnetic radiations having `lambda=310Å`are subjected to a metal sheet having work function `=12.8eV`. What will be the velocity of photoelectrons with maximum Kinetic Energy….

A

0, no emission will occur

B

`4.352xx10^(6)` m/s

C

`3.09xx10^(6)` m/s

D

`8.72xx10^(6)` m/s

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise Level- 1|1 Videos
  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise level 2|1 Videos
  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos

Similar Questions

Explore conceptually related problems

Electrons from n = 2 to n= 1 in hydrogen atom is made to fall on a metal surface with work function 1.2ev. The maximum velocity of photo electrons emitted is nearly equal to

Two photons of energy 2.5 eV and 3.5 eV fall on a metal surface on work function 1.5 eV. The ratio of the maxium velocities of the photoelectrons emitted from the metal surface is

When a metal surface is exposed to certain frequency of electromagnetic radiation. The kinetic energy of electron ejected from metal surface is 0.20 eV. If its work function (W_(0)) is 4.80 eV, the approximate frequency of radiation falling on the metal surface in Hz is

Light of described at a place by the equation E=(100)[sin5xx10^(15)]t+sin(8xx10^(15))t] falls on a metal surface having work function 2.0 eV. Calculate the maximum kinetic energy of the photoelectrons.

A photon incident on a metal of photo electric work function 2 ev produced photo electron of maximum kinetic energy 2 ev. The wave length associated with the photon is

The work function of a metal is 4.2eV. If the radiation of 2000Å falls on the metal, find the kinetic energy of the metal

Radiations of two different frequencies whose photon energies are 3.4 eV and 8.2 eV successively illuminate a metal surface whose work function is 1.8eV. The ratio of the maximum speeds of the emitted electrons will be

When electromagnetic radiations of wave length 300nm falls on the surface of sodium, electrons are emitted with a kinetic energy of 1.68xx10^(5) J "mol"^(-1) . What is the minimum energy needed to remove an electron from sodium ? What is the maximum wavelength that will cause a photoelectron to be emitted ?