A dye absorbs a photon of wavelength `lambda` and re`-` emits the same energy into two phorons of wavelengths `lambda_(1)` and `lambda_(2)` respectively. The wavelength `lambda` is related with `lambda_(1)` and `lambda_(2)` as `:`
If lambda_(1) and lambda_(2) are the wavelengths of the first members of the Lyman and Paschen series, respectivley, then lambda_(1) : lambda_(2) is
The two elements have their atomic numbers as Z_1 and Z_2 The ratio of the wavelength lambda_1 and lambda_2 corresponding to their K_alpha lines is
The first line is the Lyman series has wavelength lambda .The first line in Balmer series has wavelength
Two bodies Aand B of equal surface area have thermal emissivities of 0.01 and 0.81 respectively . The two bodies are radiating energy at the same rate. Maximum energy is radiated from the two bodies A and B at wavelength lambda _(A) and lambda _(B) respectively . Difference in these two wavelengths is 1 mu m . If the temperature of the body A is 5802 K, then value of lambda_(B) is
Wave lengths of the light absorbed by [Ni(H_(2)O)_(6)]^(2+) and [Ni(e n)_(3)]^(2+) are respectively lambda_(1) and lambda_(2) . What is the relation between lambda_(1) and lambda_(2)
What is the relation among speed of wave (v), wavelength ( lambda ) and frequency (f) ?
