The radii of maximum probability for 3s, 3p and 3d electrons are in the order :
A
`(r_(max))3dgt(r_(max))3pgt(r_(max))3s`
B
`(r_(max))3dgt(r_(max))3sgt(r_(max))3p`
C
`(r_(max))3sgt(r_(max))3pgt(r_(max))3d`
D
None of these
Text Solution
Verified by Experts
Topper's Solved these Questions
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise Level- 1|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
Similar Questions
Explore conceptually related problems
Statement (A) : Subshells, s, p. d and f can have a maximum of 1, 3, 5 and 7 electrons respectively. Statement (B) : The maximum number electrons in any shell is 2n^2 .
(A) : The radial probability distribution curves of 1s, 2p, 3d orbitals are identical in shape (R) : The number of nodal planes present in these orbitals is different
What are the values of the orbital angular momentum of an electron in the orbitals 1s, 3s, 3d and 2p ?
The orbital angular momentum of 3p electrons is :
What may be the stable oxidation state of the transition element with the following d electron configurations in the ground state of their atoms : 3d^(3) 3d^(5) 3d^(8) and 3d^(4) ?
Suneetha (A) : Third period contain 18 elements, because it has 3 subshells namely 3s, 3p and 3d. Sreelatha (B) : Third period has 8 elements, because while electrons are being filled into the shell '3d’ gets. electrons only after '4s' is filled.
lonic radii (in oversetoA ) of As^(3+) , Sb^(3+) and Bi^(3+) follow the order
The electronic configuration of four elements L, P, Q and R are given below. L- 1s^2 2s^2 2p^4 P- 1s^2 2s^2 2p^6 3s^1 Q- 1^2 2s^2 2p^6 3s^2 3p^5 R- 1s^2 2s^2 2p^6 3s^2 . Which of the following are correct compounds formed by these elements?
What is the maximum number of electrons in a sub-shell (s, p, d, f) ? Where Z = 0, I , 2, 3 ......?
Give the order of filling of electrons in the following orbitals 3p, 3d,4p, 3d and 6s.
