The behaviour of an electron in an atom is described mathematically by a wave function, or orbital. Spin of the electron produce angular momentum equal to `S= sqrt(s(s+1)) (h)/(2pi) ` where` S= +1/2`. Total spin of an atom`=+ n/2 ` or ` h/2` Where n is the number of unpaired electron.
The substance which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. The paramagnetism is expressed in terms of magnetic moment the magnetic moment of an atom
`mu_s sqrt(s(s+1)) (eh)/(2pi mc) = sqrt((n/2)(n/2+1)) (eh)/(2pi mc) s = n/2 implies mu_s = sqrt(n(n+2)) B.M`
n = number of unpaired electrons
1 B.M. (Bohr magneton) = `(eh)/(4pi mc)`
If magnetic moment is zero the substances is di-magnetic.
Which of the following ion has lowest magnetic moement.
The behaviour of an electron in an atom is described mathematically by a wave function, or orbital. Spin of the electron produce angular momentum equal to `S= sqrt(s(s+1)) (h)/(2pi) ` where` S= +1/2`. Total spin of an atom`=+ n/2 ` or ` h/2` Where n is the number of unpaired electron.
The substance which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. The paramagnetism is expressed in terms of magnetic moment the magnetic moment of an atom
`mu_s sqrt(s(s+1)) (eh)/(2pi mc) = sqrt((n/2)(n/2+1)) (eh)/(2pi mc) s = n/2 implies mu_s = sqrt(n(n+2)) B.M`
n = number of unpaired electrons
1 B.M. (Bohr magneton) = `(eh)/(4pi mc)`
If magnetic moment is zero the substances is di-magnetic.
Which of the following ion has lowest magnetic moement.
The substance which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. The paramagnetism is expressed in terms of magnetic moment the magnetic moment of an atom
`mu_s sqrt(s(s+1)) (eh)/(2pi mc) = sqrt((n/2)(n/2+1)) (eh)/(2pi mc) s = n/2 implies mu_s = sqrt(n(n+2)) B.M`
n = number of unpaired electrons
1 B.M. (Bohr magneton) = `(eh)/(4pi mc)`
If magnetic moment is zero the substances is di-magnetic.
Which of the following ion has lowest magnetic moement.
A
`Fe^(2+)`
B
`Mn^(2+)`
C
`Cr^(3+)`
D
`V^(3+)`
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The behaviour of an electron in an atom is described mathematically by a wave function, or orbital. Spin of the electron produce angular momentum equal to S= sqrt(s(s+1)) (h)/(2pi) where S= +1/2 . Total spin of an atom =+ n/2 or h/2 Where n is the number of unpaired electron. The substance which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. The paramagnetism is expressed in terms of magnetic moment the magnetic moment of an atom mu_s sqrt(s(s+1)) (eh)/(2pi mc) = sqrt((n/2)(n/2+1)) (eh)/(2pi mc) s = n/2 implies mu_s = sqrt(n(n+2)) B.M n = number of unpaired electrons 1 B.M. (Bohr magneton) = (eh)/(4pi mc) If magnetic moment is zero the substances is di-magnetic. If an ion of ""_(25)Mn has a magnetic of 3.873 B.M. Then Mn is in which state.
The species which contains unpaired electrons is
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The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of magnetic moment. The magnetic moment is related to the number of unpaired electrons according to the following relation : Magnetic moment, mu = sqrt(n(n+2)) B.M. Where .n. = number of unpaired electrons. B.M. stands for Bohr magneton, a unit of magnetic moment. Which of the following is diamagnetic ?
The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of magneticmoment The magnetic moment is related to the number of unpaired electrons according to the following relation : Magnetic moment, mu = sqrt(n(n+2)) B.M. Where ‘n’ = number of unpaired electrons. B.M stands for Bohr magneton, a unit of magnetic moment. Which of the following has the highest magnetic moment ?
In 1s^1 2s^2 2p^4 the number of unpaired electrons in ground state are
The number of unpaired electrons in 1s^(2) 2s^(2) 2p^(3) is
The number of unpaired electrons in 1s^(2)2s^(2)2p^(3) is
The number of unpaired electrons in 1s^(2)2s^(2)2p^(3) is
The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of magnetic moment. The magnetic moment is related to the number of unpaired electrons according to the following relation : Magnetic moment, mu = sqrt(n(n+2)) B.M. Where .n. = number of unpaired electrons. B.M. stands for Bohr magneton, a unit of magnetic moment. An ion of a d-block elements has magnetic moment 5.92 B.M. Select the ion among the following.